Advertisements
Advertisements
प्रश्न
Simplify the following
`(a^(3n-9))^6/(a^(2n-4))`
Advertisements
उत्तर
`(a^(3n-9))^6/(a^(2n-4))`
`=a^(6(3n-9))/a^(2n-4)`
`=a^(18n-54)/a^(2n-4)`
`=a^(18n-54)xxa^-(2n-4)`
`=a^(18n-54)xxa^(-2n+4)`
`=a^(18n-54-2n+4)`
`=a^(16n-50)`
APPEARS IN
संबंधित प्रश्न
Find:-
`64^(1/2)`
Simplify the following:
`(2x^-2y^3)^3`
Prove that:
`(a+b+c)/(a^-1b^-1+b^-1c^-1+c^-1a^-1)=abc`
Simplify the following:
`(5xx25^(n+1)-25xx5^(2n))/(5xx5^(2n+3)-25^(n+1))`
Prove that:
`((0.6)^0-(0.1)^-1)/((3/8)^-1(3/2)^3+((-1)/3)^-1)=(-3)/2`
Show that:
`(x^(a-b))^(a+b)(x^(b-c))^(b+c)(x^(c-a))^(c+a)=1`
If `x=2^(1/3)+2^(2/3),` Show that x3 - 6x = 6
If 1176 = `2^axx3^bxx7^c,` find the values of a, b and c. Hence, compute the value of `2^axx3^bxx7^-c` as a fraction.
If 24 × 42 =16x, then find the value of x.
If x is a positive real number and x2 = 2, then x3 =
