Advertisements
Advertisements
प्रश्न
Show that the value of x is 11, when `("x"^3 + "3x")/(3"x"^2 + 1) = 341/91`
Advertisements
उत्तर
`("x"^3 + "3x")/(3"x"^2 + 1) = 341/91`
⇒ 91(x3 + 3x) = 341(3x2 + 1)
⇒ 91x3 - 1023x2 + 273x - 341 = O
LHS
91x3 - 1023x2 + 273x - 341
= 91( 11 × 11 × 11) - 1023 (11 × 11) + 273 (11) -341
= (91 × 1331) - (1023 × 121) + (273 × 11) - 341
= 121121 - 123783 + 3003 - 341
= 0= RHS
LHS = RHS.
Hence x = 11
APPEARS IN
संबंधित प्रश्न
Find the ratio of the speed of a cycle 15 km per hour to the speed of scooter 30 km per hour.
Find triplicate ratio of `m/2 : n/3`
Find the value of x, if: (2x + 1) : (3x + 13) is the sub-duplicate ratio of 9 : 25.
Divide a number into two parts in the ratio 5:7 so that smaller part is 60. Find the number.
If `x/a = y/b = z/c` show that: `x^3/a^3 + y^3/b^3 + z^3/c^3 = (3xyz)/(abc)`.
Find the ratio of the first quantity to the second.
60 paise, 1 rupee
From the given pairs, find which ratio is larger:
(3 : 7) or (4 : 9)
An alloy contains only zinc and copper and they are in the ratio of 7 : 9. If the weight of the alloy is 8 kg, then find the weight of copper in the alloy.
In the following figure, division represents 1 cm:
Express numerically the ratios of the following distances:
BF : AI
Find the ratio of the following:
40 cm to 1.5 m
