हिंदी

Sanjay is looking for one-bedroom apartment on rent. At Neelgiri apartments, rent for the first two months is 20% off. The one-bedroom rate at Neelgiri is Rs 6,000 per month. - Mathematics

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प्रश्न

Sanjay is looking for one-bedroom apartment on rent. At Neelgiri apartments, rent for the first two months is 20% off. The one-bedroom rate at Neelgiri is Rs 6,000 per month. At Savana apartments, the first month is 50% off. The one-bedroom rate at Savana apartments is Rs 7000 per month. Which apartment will be cheaper for the first two months? By how much?

योग
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उत्तर

Given, one-bedroom rate at Neelgiri = 6000 per month

Also, 20% off for first two months

We need to calculate the cheaper apartment

⇒ Now, we know x% of `n = x/100xx n`

⇒ 20% of rent = `20/100 xx 6000` = 1200

⇒ Rent for first two months = 2 × (6000 – 1200)

= 2 × 4800

= Rs. 9600 

∴ Rent for first two months at Neelgiri apartments = Rs. 9600

At Savana apartments, 50% off for first month

And rent for bedroom = 7000 per month

⇒ 50% off rent = `50/100 xx 7000` = Rs. 3500

⇒ Rent for first month = Rs. 7000 – Rs. 3500 = Rs. 3500

But, we need rent for two months for comparing

⇒ Rent for two months in savanna apartment = 3500 + 7000 = Rs. 10500

Now, comparing two apartments rent, we get

= Rs. 10500 – Rs. 9600

= Rs. 900

Hence, Neelgiri apartment will be cheaper by Rs. 900

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अध्याय 9: Comparing Quantities - Exercise [पृष्ठ ३०१]

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एनसीईआरटी एक्झांप्लर Mathematics [English] Class 8
अध्याय 9 Comparing Quantities
Exercise | Q 111. | पृष्ठ ३०१

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