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प्रश्न
Rationalise the denominator:
`9/(sqrt(11) + sqrt(5))`
योग
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उत्तर
We are given:
`9/(sqrt(11) + sqrt(5))`
Step 1: Multiply numerator and denominator by the conjugate of the denominator:
`9/(sqrt(11) + sqrt(5)) xx (sqrt(11) - sqrt(5))/(sqrt(11) - sqrt(5))`
= `(9(sqrt(11) - sqrt(5)))/((sqrt(11) + sqrt(5))(sqrt(11) - sqrt(5))`
Step 2: Use identity (a + b)(a – b) = a2 – b2:
`(sqrt(11) + sqrt(5))(sqrt(11) - sqrt(5))`
= `(sqrt(11))^2 - (sqrt(5))^2`
= 11 – 5
= 6
Step 3: Final simplification:
`(9(sqrt(11) - sqrt(5)))/6`
= `3/2 (sqrt(11) - sqrt(5))`
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अध्याय 1: Rational and Irrational Numbers - MISCELLANEOUS EXERCISE [पृष्ठ १७]
