हिंदी

Ramkali saved Rs 5 in the first week of a year and then increased her weekly saving by Rs 1.75. If in the nth week, her week, her weekly savings become Rs 20.75, find n.

Advertisements
Advertisements

प्रश्न

Ramkali saved Rs 5 in the first week of a year and then increased her weekly saving by Rs 1.75. If in the nth week, her week, her weekly savings become Rs 20.75, find n.

योग
Advertisements

उत्तर

Given that,

a = 5

d = 1.75

an = 20.75

n = ?

an = a + (n − 1) d

⇒ 207.50 = 50 + (n - 1) (17.5)

⇒ 207.50 = 50 + 17.5n - 17.5

⇒ 17.5n = 207.50 + 17.5 - 50

⇒ 17.5n = 225 - 50

⇒ 17.5n = 175

⇒ n = `175/17.5`

⇒ n = 10

Hence, n is 10.

shaalaa.com
  क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
अध्याय 5: Arithmetic Progressions - EXERCISE 5.2 [पृष्ठ ६३]

APPEARS IN

एनसीईआरटी Mathematics [English] Class 10
अध्याय 5 Arithmetic Progressions
EXERCISE 5.2 | Q 20. | पृष्ठ ६३
एमएल अग्रवाल Understanding Mathematics [English] Class 10 ICSE
अध्याय 9 Arithmetic and Geometric Progressions
Exercise 9.2 | Q 26

संबंधित प्रश्न

How many terms of the series 54, 51, 48, …. be taken so that their sum is 513 ? Explain the double answer


If the mth term of an A.P. is 1/n and the nth term is 1/m, show that the sum of mn terms is (mn + 1)


Find the 20th term from the last term of the A.P. 3, 8, 13, …, 253.


Find the four numbers in A.P., whose sum is 50 and in which the greatest number is 4 times the least.


Find the sum of the following arithmetic progressions: 50, 46, 42, ... to 10 terms


Find the sum of the following arithmetic progressions:

1, 3, 5, 7, ... to 12 terms


Show that the sum of all odd integers between 1 and 1000 which are divisible by 3 is 83667.


Find the sum of the first 15 terms of each of the following sequences having the nth term as

bn = 5 + 2n


Which term of the A.P. `20, 19 1/4, 18 1/2, 17 3/4,` ..... is the first negative term?


Find the sum of  the following Aps:

9, 7, 5, 3 … to 14 terms


The sum of the first n terms of an AP is given by  `s_n = ( 3n^2 - n) ` Find its

(i) nth term,
(ii) first term and
(iii) common difference.

 


Find the sum of all even numbers between 1 and 350.

If the 9th term of an A.P. is zero then show that the 29th term is twice the 19th term?


Choose the correct alternative answer for  the following question . 

In an A.P. first two terms are –3, 4 then 21st term is ...


Choose the correct alternative answer for  the following question .

 In an A.P. 1st term is 1 and the last term is 20. The sum of all terms is = 399 then n = ....


In an A.P. the first term is – 5 and the last term is 45. If the sum of all numbers in the A.P. is 120, then how many terms are there? What is the common difference?


If the sum of a certain number of terms starting from first term of an A.P. is 25, 22, 19, ..., is 116. Find the last term.


If the 10th term of an A.P. is 21 and the sum of its first 10 terms is 120, find its nth term.

 

Write the nth term of an A.P. the sum of whose n terms is Sn.

 

The first and last term of an A.P. are a and l respectively. If S is the sum of all the terms of the A.P. and the common difference is given by \[\frac{l^2 - a^2}{k - (l + a)}\] , then k =

 

 


The common difference of the A.P.

\[\frac{1}{3}, \frac{1 - 3b}{3}, \frac{1 - 6b}{3}, . . .\] is 
 

In a Arithmetic Progression (A.P.) the fourth and sixth terms are 8 and 14 respectively. Find that:
(i) first term
(ii) common difference
(iii) sum of the first 20 terms. 


In an A.P. sum of three consecutive terms is 27 and their products is 504. Find the terms. (Assume that three consecutive terms in an A.P. are a – d, a, a + d.)


Find the sum of first 1000 positive integers.

Activity :- Let 1 + 2 + 3 + ........ + 1000

Using formula for the sum of first n terms of an A.P.,

Sn = `square`

S1000 = `square/2 (1 + 1000)`

= 500 × 1001

= `square`

Therefore, Sum of the first 1000 positive integer is `square`


What is the sum of an odd numbers between 1 to 50?


If sum of first 6 terms of an AP is 36 and that of the first 16 terms is 256, find the sum of first 10 terms.


Jaspal Singh repays his total loan of Rs. 118000 by paying every month starting with the first instalment of Rs. 1000. If he increases the instalment by Rs. 100 every month, what amount will be paid by him in the 30th instalment? What amount of loan does he still have to pay after the 30th instalment?


If the first term of an A.P. is p, second term is q and last term is r, then show that sum of all terms is `(q + r - 2p) xx ((p + r))/(2(q - p))`.


Solve the equation:

– 4 + (–1) + 2 + 5 + ... + x = 437


Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×