हिंदी

Prove the following identities: (cos2A – 1) (cot2A + 1) = −1

Advertisements
Advertisements

प्रश्न

Prove the following identities: 

(cos2A – 1) (cot2A + 1) = −1

योग
Advertisements

उत्तर

L.H.S. = (cos2A – 1) (cot2A + 1)

= – (1 – cos2A)(1 + cot2A)

= – sin2A · cosec2A

= `- sin^2"A" xx 1/sin^2"A"`

= – 1

= R.H.S.

shaalaa.com
  क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
अध्याय 2: Trigonometry - 1 - EXERCISE 2.2 [पृष्ठ ३१]

APPEARS IN

बालभारती Mathematics and Statistics (Arts and Science) Part 1 [English] Standard 11 Maharashtra State Board
अध्याय 2 Trigonometry - 1
EXERCISE 2.2 | Q 15) ii) | पृष्ठ ३१

संबंधित प्रश्न

Evaluate the following:

sin 30° + cos 45° + tan 180°


Evaluate the following : 

sin 30° × cos 45° × tan 360°


If tanθ = `1/2`, evaluate `(2sin theta + 3cos theta)/(4cos theta + 3sin theta)`


Eliminate θ from the following: 

x = 3secθ , y = 4tanθ


Eliminate θ from the following :

x = 5 + 6cosecθ, y = 3 + 8cotθ


Find the acute angle θ such that 2 cos2θ = 3 sin θ.


Find sinθ such that 3cosθ + 4sinθ = 4


If cosecθ + cotθ = 5, then evaluate secθ.


Prove the following identities:

`(1 + tan^2 "A") + (1 + 1/tan^2"A") = 1/(sin^2 "A" - sin^4"A")`


Prove the following identities:

`tan^3theta/(1 + tan^2theta) + cot^3theta/(1 + cot^2theta` = secθ cosecθ – 2sinθ cosθ


Prove the following identities:

`cottheta/("cosec"  theta - 1) = ("cosec"  theta + 1)/cot theta`


Prove the following identities:

`(1 - sectheta + tan theta)/(1 + sec theta - tan theta) = (sectheta + tantheta - 1)/(sectheta + tantheta + 1)`


Select the correct option from the given alternatives: 

`tan"A"/(1 + sec"A") + (1 + sec"A")/tan"A"` is equal to


Select the correct option from the given alternatives:

If θ = 60°, then `(1 + tan^2theta)/(2tantheta)` is equal to


Select the correct option from the given alternatives:

If cosecθ + cotθ = `5/2`, then the value of tanθ is


Select the correct option from the given alternatives:

If cosecθ − cotθ = q, then the value of cot θ is


Select the correct option from the given alternatives:

The value of tan1°.tan2°tan3°..... tan89° is equal to


Prove the following:  

sin2A cos2B + cos2A sin2B + cos2A cos2B + sin2A sin2B = 1


Prove the following:

`((1 + cot theta + tan theta)(sin theta - costheta)) /(sec^3theta - "cosec"^3theta)`= sin2θ cos2θ


Prove the following:

`(tan theta + 1/costheta)^2 + (tan theta - 1/costheta)^2 = 2((1 + sin^2theta)/(1 - sin^2theta))`


Prove the following:

sin4θ + cos4θ = 1 – 2 sin2θ cos2θ


Prove the following:

2(sin6θ + cos6θ) – 3(sin4θ + cos4θ) + 1 = 0


Prove the following:

(sinθ + cosecθ)2 + (cosθ + secθ)2 = tan2θ + cot2θ + 7


Prove the following:

sin6A + cos6A = 1 − 3sin2A + 3 sin4A


Prove the following:

(1 + tanA · tanB)2 + (tanA − tanB)2 = sec2A · sec2B


Prove the following:

`(1 + cottheta  +  "cosec" theta)/(1 - cottheta  +  "cosec" theta) = ("cosec" theta  + cottheta - 1)/(cottheta - "cosec"theta + 1)`


Prove the following:

`("cosec"theta + cottheta - 1)/( "cosec"theta + cot theta + 1) =(1-sintheta)/costheta`


Prove the following identity:

`(1 - sec theta + tan theta)/(1 + sec theta - tan theta) = (sec theta + tan theta - 1)/(sec theta + tan theta + 1)`


If 5 tan θ = 4. then `(5 sin θ − 3 cos θ)/(5 sin θ + 2 cos θ)` = ______. 


Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×