Advertisements
Advertisements
प्रश्न
Prove that :
`[ x^(a(b - c))]/[x^b(a - c)] ÷ ((x^b)/(x^a))^c = 1`
Advertisements
उत्तर
We need to prove that
`[ x^(a(b - c))]/[x^b(a - c)] ÷ ((x^b)/(x^a))^c = 1`
LHS =
= `x^[a(b - c ) - b( a - c )] ÷ x^(bc)/x^(ac)`
= `x^( ab - ac - ab + bc ) ÷ x^( bc - ac )`
= `x^( ab - ac - ab + bc - bc + ac )`
= `x^0`
= 1
= RHS
APPEARS IN
संबंधित प्रश्न
Find x, if : `sqrt( 2^( x + 3 )) = 16`
Solve for x:
`2^(3x + 3) = 2^(3x + 1) + 48`
Evaluate : `[(-2/3)^-2]^3 xx (1/3)^-4 xx 3^-1 xx 1/6`
Solve : 3x-1× 52y-3 = 225.
Evaluate the following:
`(2^3 xx 3^5 xx 24^2)/(12^2 xx 18^3 xx 27)`
Evaluate the following:
`(2^6 xx 5^-4 xx 3^-3 xx 4^2)/(8^3 xx 15^-3 xx 25^-1)`
Evaluate the following:
`9^(5/2) - 3 xx 5^0 - (1/81)^((-1)/2)`
Find the value of k in each of the following:
`root(4)root(3)(x^2)` = xk
Show that : `(1)/(1 + "a"^("p"- "q")) + (1)/(1 + "a"^("q"- "p")`
Prove the following:
(xa)b-c x (xb)c-a x (xc)a-b = 1
