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Prove that sin(30° + θ) + cos(60° + θ) = cos θ

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प्रश्न

Prove that sin(30° + θ) + cos(60° + θ) = cos θ

योग
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उत्तर

sin(30° + θ) + cos(60° + θ) = cos θ

sin(30° + θ) + cos(60° + θ)

= sin 30° cos θ + cos 30° sin θ + cos 60° cos θ – sin 60° sin θ

= `1/2  cos theta + sqrt(3)/2  sin theta + 1/2  cos theta - sqrt(3)/2 sin theta`

= cos θ

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Trigonometric Functions and Their Properties
  क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
अध्याय 3: Trigonometry - Exercise 3.4 [पृष्ठ १०९]

APPEARS IN

सामाचीर कलवी Mathematics - Volume 1 and 2 [English] Class 11 TN Board
अध्याय 3 Trigonometry
Exercise 3.4 | Q 9. (ii) | पृष्ठ १०९

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