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Prove that the Function F(X) = X3 − 6x2 + 12x − 18 is Increasing on R ?

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प्रश्न

Prove that the function f(x) = x3 − 6x2 + 12x − 18 is increasing on R ?

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उत्तर

\[f\left( x \right) = x^3 - 6 x^2 + 12x - 18\]

\[f'\left( x \right) = 3 x^2 - 12x + 12\]

\[ = 3\left( x^2 - 4x + 4 \right)\]

\[ = 3 \left( x - 2 \right)^2 \geq 0, \forall x \text { in R } \left[ \because 3 > 0 \text { &} \left( x - 2 \right)^2 \geq 0 \right]\]

\[\text { So, f(x) is increasing on R } .\]

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अध्याय 16: Increasing and Decreasing Functions - Exercise 17.2 [पृष्ठ ३५]

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आर.डी. शर्मा Mathematics Volume 1 and 2 [English] Class 12
अध्याय 16 Increasing and Decreasing Functions
Exercise 17.2 | Q 21 | पृष्ठ ३५

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