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Prove That: Cos 4 a + Cos 3 a + Cos 2 a Sin 4 a + Sin 3 a + Sin 2 a = Cot 3 a - Mathematics

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प्रश्न

Prove that:

\[\frac{\cos 4A + \cos 3A + \cos 2A}{\sin 4A + \sin 3A + \sin 2A} = \cot 3A\]

 

योग
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उत्तर

 Consider LHS: 
\[ \frac{\cos 4A + \cos 3A + \cos 2A}{\sin 4A + \sin 3A + \sin 2A}\]
\[ = \frac{\cos 4A + \cos 2A + \cos 3A}{\sin 4A + \sin 2A + \sin 3A}\]
\[ = \frac{2\cos \left( \frac{4A + 2A}{2} \right) \cos \left( \frac{4A - 2A}{2} \right) + \cos 3A}{2\sin \left( \frac{4A + 2A}{2} \right) \cos \left( \frac{4A - 2A}{2} \right) + \sin 3A}\]
\[ \]
\[ = \frac{2\cos 3A \cos A + \cos 3A}{2\sin 3A \cos A + \sin 3A}\]
\[ = \frac{\cos 3A\left[ 2\cos A + 1 \right]}{\sin 3A\left[ 2\cos A + 1 \right]}\]
\[ = \cot 3A\]
= RHS
Hence, RHS = LHS.

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Transformation Formulae
  क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
अध्याय 8: Transformation formulae - Exercise 8.2 [पृष्ठ १८]

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आरडी शर्मा Mathematics [English] Class 11
अध्याय 8 Transformation formulae
Exercise 8.2 | Q 8.03 | पृष्ठ १८

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