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Prove that 1 + cos 2x + cos 4x + cos 6x = 4 cos x cos 2x cos 3x

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प्रश्न

Prove that 1 + cos 2x + cos 4x + cos 6x = 4 cos x cos 2x cos 3x

योग
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उत्तर

4 cos x cos 2x . cos 3x = 4 cos x . cos 3x . cos 2x

= 4 cos x . [cos (3x + 2x) + cos (3x – 2x)]

2 cos x . [cos 5x + cos x] = 2 cos 5x . cos x + 2 cos2x

= 2 × `1/2` [cos (5x + x) + cos (5x – x)] + 1 + cos 2x

= cos 6x + cos 4x + 1 + cos 2x

= 1 + cos 2x + cos 4x + cos 6x

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Trigonometric Functions and Their Properties
  क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
अध्याय 3: Trigonometry - Exercise 3.6 [पृष्ठ १२१]

APPEARS IN

सामाचीर कलवी Mathematics - Volume 1 and 2 [English] Class 11 TN Board
अध्याय 3 Trigonometry
Exercise 3.6 | Q 9 | पृष्ठ १२१

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