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P 2 G of Hydrogen is Sealed in a Vessel of Volume 0.02 M3 and is Maintained at 300 K. Calculate the Pressure in the Vessel.

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प्रश्न

2 g of hydrogen is sealed in a vessel of volume 0.02 m3 and is maintained at 300 K. Calculate the pressure in the vessel.

Use R=8.3J K-1 mol-1

योग
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उत्तर

Given:
Mass of hydrogen, m = 2 g
Volume of the vessel, V = 0.02 m3
Temperature in the vessel, T = 300 K
Molecular mass of the hydrogen, M = 2 u

No of moles, n =\[\frac{m}{M} = \frac{2}{2}\]= 1 mole

Rydberg's constant, R = 8.3 J/Kmol

From the ideal gas equation, we get

PV = nRT

\[\Rightarrow P = \frac{nRT}{V}\] 

\[ \Rightarrow P = \frac{1 \times 8 . 3 \times 300}{0 . 02}\]

\[\Rightarrow\]P = 1.24 × 105 Pa

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Kinetic Theory of Gases - Concept of Pressure
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अध्याय 24: Kinetic Theory of Gases - Exercises [पृष्ठ ३४]

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एचसी वर्मा Concepts of Physics Volume 1 and 2 [English]
अध्याय 24 Kinetic Theory of Gases
Exercises | Q 8 | पृष्ठ ३४

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