हिंदी

Non-metals are usually poor conductors of heat and electricity. They are non-lustrous, non-sonorous, non-malleable and are coloured. Name a lustrous non-metal.

Advertisements
Advertisements

प्रश्न

Non-metals are usually poor conductors of heat and electricity. They are non-lustrous, non-sonorous, non-malleable and are coloured.

Name a lustrous non-metal.

एक शब्द/वाक्यांश उत्तर
Advertisements

उत्तर

Iodine

shaalaa.com
  क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
अध्याय 2: Is Matter Around Us Pure - Short Answer Questions [पृष्ठ १६]

APPEARS IN

एनसीईआरटी एक्झांप्लर Science Exemplar [English] Class 9
अध्याय 2 Is Matter Around Us Pure
Short Answer Questions | Q 30. (a) | पृष्ठ १६

वीडियो ट्यूटोरियलVIEW ALL [1]

संबंधित प्रश्न

Calculate the amount of carbon dioxide that could be produced when 1 mole of carbon is burnt in air.


Why does the molarity of a solution depend upon temperature?


Solve the following problem:

Write the following number in ordinary decimal form:

0.00477 × 105


Solve the following problem:

Perform the following calculation. Round off your answer to two digits.

`33/(9.00xx10^-4)`


Solve the following problem:

Perform the following calculation. Round off your answer to two digits.

`((4xx10^-3)(9.9xx10^-7))/((789)(1.002xx10^-10)(0.3xx10^2))`


Solve the following problem:

Your laboratory partner was given the task of measuring the length of a box (approx 5 in) as accurately as possible, using a metre stick graduated in milimeters. He supplied you with the following measurements:

12.65 cm, 12.6 cm, 12.65 cm, 12.655 cm, 126.55 mm, 12 cm.

State which of the measurements you would accept, giving the reason.


Sulphuric acid reacts with sodium hydroxide as follows:

\[\ce{H2SO4 + 2NaOH -> Na2SO4 + 2H2O}\]

When 1 L of 0.1 M sulphuric acid solution is allowed to react with 1 L of 0.1 M sodium hydroxide solution, the amount of sodium sulphate formed and its molarity in the solution obtained is:

(i) 0.1 mol L–1

(ii) 7.10 g

(iii) 0.025 mol L–1

(iv) 3.55 g


If 4 g of \[\ce{NaOH}\] dissolves in 36 g of \[\ce{H2O}\], calculate the mole fraction of each component in the solution. Also, determine the molarity of solution (specific gravity of solution is 1g mL–1).


What quantity (in mL) of a 45% acid solution of a monoprotic strong acid must be mixed with a 20% solution of the same acid to produce 800 mL of a 29.875% acid solution?


Molarity is ______.


Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×