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Newton'S Law of Cooling is a Special Case of

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प्रश्न

Newton's law of cooling is a special case of

विकल्प

  • Wien's displacement law

  • Kirchhoff's law

  • Stefan's law

  • Planck's law

MCQ
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उत्तर

Stefan's law

From Stefan-Boltzman's law, the energy of the thermal radiation emitted per unit time by a blackbody of surface area A is given by, `u = σAT^4`
Where `σ`  is Stefan's constant.
Suppose a body at temperature T is kept in a room at temperature T0.

According to Stefan's law, energy of the thermal radiation emitted by the body per unit time is `u = eσAT^4`
Here, e is the emissivity of the body.
The energy absorbed per unit time by the body is (due to the radiation emitted by the walls of the room 
`Δu = eσAT_0^4`
Thus, the net loss of thermal energy per unit time is 
`Δu = eσA ( T^4 - T_0^4 )`
Newton law of cooling is given by
`(dT)/(dt) = -bA( T - T_0 )`
This can be obtained from equation (i) by considering the temperature difference to be small and doing the binomial expansion.

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अध्याय 28: Heat Transfer - MCQ [पृष्ठ ९७]

APPEARS IN

एचसी वर्मा Concepts of Physics Volume 1 and 2 [English]
अध्याय 28 Heat Transfer
MCQ | Q 7 | पृष्ठ ९७

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