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प्रश्न
Name the chloride of a metal which is soluble in excess of ammonium hydroxide. Write equation for the same.
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उत्तर १
Zinc chloride (ZnCl2) is soluble in excess of ammonium hydroxide.
\[\ce{\underset{\text{colourless}}{ZnCl2} + 2NH4OH -> \underset{\text{white gelatinous ppt.}}{Zn(OH)2↓} + 2NH4Cl}\]
With excess of NH4OH ppt dissolves
\[\ce{Zn(OH)2 + 2NH4Cl + 2NH4OH(excess) -> \underset{\text{Tetrammine zinc(ll)chloride colourless}}{[Zn(NH3)4]Cl2 + 4H2O}}\]
उत्तर २
It is silver chloride [AgCl] dissolves in excess of NH4OH.
A product formed is [Ag(NH3)2]Cl [Soluble colourless Diamine Argentous (Z) chloride]
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संबंधित प्रश्न
Identify the substance underlined, in the following case:
Cation that does not form a precipitate with ammonium hydroxide but forms one with sodium hydroxide.
Name a white, insoluble oxide that dissolves when fused with caustic soda or caustic potash.
Using sodium hydroxide solution, how will you distinguish:
Lead hydroxide from magnesium hydroxide.
Identify the substance Q based on the information given below:
The white crystalline solid Q is soluble in water. It liberates a pungent smelling gas when heated with sodium hydroxide solution.
Distinguish by adding:
Sodium hydroxide solution and ammonium hydroxide solution to lead nitrate solution and zinc nitrate solution.
Distinguish by adding:
Sodium hydroxide solution and ammonium hydroxide solution to copper salt solution and ferrous salt solution.
Distinguish by adding:
Sodium hydroxide solution and ammonium hydroxide solution to Fe(II) salt solution and Fe(III) salt solution.
Distinguish by adding:
Sodium hydroxide solution and ammonium hydroxide solution to ferrous nitrate and lead nitrate.
Identify the cation in the following case:
Sodium hydroxide solution when added to Solution C gives a white precipitate which is insoluble in excess of sodium hydroxide solution.
State one relevant observation for the following:
To the copper nitrate solution, initially, few drops of sodium hydroxide solution is added and then added in excess.
