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Mr. Pradip Deposited Rs 2,400 Pm in Bank for One Year 6 Months Under the Recurring Deposit Scheme. If the Maturity Value of His Deposit is Rs 47,304 Find the Rate of Interest per Annum. - Mathematics

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प्रश्न

Mr. Pradip deposited  Rs 2,400 pm in bank for One year 6 months under the recurring deposit scheme. If the maturity value of his deposit is Rs 47,304 find the rate of interest per annum.

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उत्तर

Given that Recurring deposit per month =Rs 2400, Period= 3 years = 18

Months, R=R % , Maturity value =Rs 47304

Money deposited= Monthly value x No of Months= 2400 x 18=Rs 43,200

⇒  Interest= Maturity Value - Amount deposited 

=Rs (47,304- 43,200) =Rs 4,104

Total Principal for 1 Month = 2400 x (18)(18+1)/2= Rs 4,10,400

⇒  4104 = 410400 x R /1200 ~ R= 12 % 

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अध्याय 3: Banking - Exercise 3.2 [पृष्ठ ५१]

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फ्रैंक Mathematics - Part 2 [English] Class 10 ICSE
अध्याय 3 Banking
Exercise 3.2 | Q 10 | पृष्ठ ५१

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