Advertisements
Advertisements
प्रश्न
Mohit makes 8 full rounds of a rectangular field with length = 120 m and breadth = 75 m.
John makes 10 full rounds of a square field with each side 100 in. Find who covers larger distance and by how much?
Advertisements
उत्तर
Mohit
Length of the rectangular field = 120 m
Breadth of the rectangular field = 75 m
∴ Distance covered in one round (perimeter)
= 2(1 + b) = 2(120 + 75) = 390 m
Hence, distance covered in 8 rounds = 390 x 8 m = 3120 m
John
Side of the field = 100 m
∴ Distance covered in one round = 4 x a = 4 x 100 = 400 m
Hence, Distance covered in 10 rounds = 400 x 10 m = 4000 m
John a covers greater distance then Mohit by = (4000 - 3120) m = 880 m
APPEARS IN
संबंधित प्रश्न
The length and the breadth of a rectangular field are in the ratio 5: 4 and its area is 3380 m2. Find the cost of fencing it at the rate of ₹75 per m.
Each side of a square plot of land is 55 m. Find the cost of fencing the plot at the rate of ₹32 per meter.
Find the perimeter of a regular hexagon of side 6.5 cm.
Each rectangular tile is 40 cm long and 30 cm wide. How many tiles will be required to cover the floor of a room with length = 4.8 m and breadth = 2.4 m.
If we take 4 rounds around a field that is 160 m long and 90 m wide, what is the distance we walk in kilometers?
A rectangular path of 60 m length and 3 m width is covered by square tiles of side 25 cm. How many tiles will there be in one row along its width? How many such rows will be there? Find the number of tiles used to make this path?
On a centimetre squared paper, make as many rectangles as you can, such that the area of the rectangle is 16 sq cm (consider only natural number lengths).
- Which rectangle has the greatest perimeter?
- Which rectangle has the least perimeter?
- If you take a rectangle of an area of 24 sq cm, what will be your answers?
If a wire in the shape of a square is rebent into a rectangle, then the ______ of both shapes remain same, but ______ may varry.
A hedge boundary needs to be planted around a rectangular lawn of size 72 m × 18 m. If 3 shrubs can be planted in a metre of hedge, how many shrubs will be planted in all?
Why is the perimeter of a rectangle calculated as 2 × (length + breadth)?
