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Meera Borrowed Rs 35,000 at 12.5% P.A. Simple Interest for 3 Years. She Immediately Gave It to Archana at 12 % P.A. Compound Interest Compounded Annually. - Mathematics

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प्रश्न

Meera borrowed Rs 35,000 at 12.5% p.a. simple interest for 3 years. She immediately gave it to Archana at 12 % p.a. compound interest compounded annually. Find Meera's loss or gain at the end of 3 years.

योग
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उत्तर

Here, P = Rs 35,000 ; t = 3 years

For simple interest: r=12.5 %

S.I. =`("P" xx "r" xx "t")/100`

S.I. = Rs `(35000 xx 12.5 xx 3)/100`

S.I. = Rs 13,125

For compound interest :  r =12 %  

`"A" = "P" (1 + "r"/100)^"n"`

`"A" = "Rs"  35000 xx  112/100 xx 112/100 xx 112/100`

A = Rs 49172.48 

C.I. = A - P

C.I. = Rs (49,172.48 - 35,000)

C.I. = Rs 14, 172.48 

The difference in the compound interest and the simple interest= Rs( 14, 172.4813, 125) = Rs 1,047 .48 

Meera gained Rs 1,047.48 

shaalaa.com
Finding CI from the Relation CI = A – P
  क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
अध्याय 1: Compound Interest - Exercise 1.4 [पृष्ठ १३]

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फ्रैंक Mathematics - Part 2 [English] Class 10 ICSE
अध्याय 1 Compound Interest
Exercise 1.4 | Q 10 | पृष्ठ १३

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