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Match the shape of molecules in Column I with the type of hybridisation in Column II. Column I Column II (i) Tetrahedral (a) sp2 (ii) Trigonal (b) sp (iii) Linear (c) sp3 - Chemistry

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प्रश्न

Match the shape of molecules in Column I with the type of hybridisation in Column II.

Column I Column II
(i) Tetrahedral (a) sp2
(ii) Trigonal (b) sp
(iii) Linear (c) sp3
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उत्तर

Column I Column II
(i) Tetrahedral (c) sp3
(ii) Trigonal (a) sp2
(iii) Linear (b) sp

Explanation:

(i) A tetrahedral molecule has four electron pairs and these make sigma bonds with each other. The s and p orbitals overlap with each other thus forming a sp3 hybridized molecule.

(ii) There are two possibilities for the central atom to have  sp2 hybridization. Either all the bonds are in place i.e, the bond pairs are all sigma bonds or pi bonds or there are only two bonds and one lone pair of electrons.

(iii) The sp hybridization involves the mixing of the valence electrons in s orbital with another valence electron in the p orbital which yields two sp orbitals which are oriented in a linear geometry.

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Hybridisation - Types of Hybridisation
  क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
अध्याय 4: Chemical Bonding and Molecular Structure - Multiple Choice Questions (Type - I) [पृष्ठ ४७]

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एनसीईआरटी एक्झांप्लर Chemistry [English] Class 11
अध्याय 4 Chemical Bonding and Molecular Structure
Multiple Choice Questions (Type - I) | Q 56 | पृष्ठ ४७

संबंधित प्रश्न

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Column I Column II
(i) \[\ce{SF4}\] (a) sp3d2
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\[\begin{array}{cc}
\phantom{.....}\ce{O}\\
\phantom{.....}||\\
\ce{\overset{∗}{C}H2 = CH - \overset{∗}{C} - O - H}
\end{array}\]


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\[\ce{CH3 - \overset{∗}{C}H2 - OH}\]


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\[\begin{array}{cc}
\phantom{..........}\ce{O}\\
\phantom{..........}||\\
\ce{CH3 - CH2 - \overset{∗}{C} - H}
\end{array}\]


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