Question

Let f: A → B be a function defined by f(x) = `x/2` – 1, where A = {2, 4, 6, 10, 12}, B = {0, 1, 2, 4, 5, 9}. Represent f by a table

Answer 1

A = {2, 4, 6, 10, 12}

B = {0, 1, 2, 4, 5, 9}

f(x) = `x/(2) - 1`

f(2) = `(2)/(2) - 1` = 1 – 1 = 0

f(4) = `(4)/(2) - 1` = 2 – 1 = 1

f(6) = `(6)/(2) - 1` = 3 – 1 = 2

f(10) = `(10)/(2) - 1` = 5 – 1 = 4

f(12) = `(12)/(2) - 1` = 6 – 1 = 5

X	2	4	6	10	12
f(x)	0	1	2	4	5