हिंदी
तमिलनाडु बोर्ड ऑफ सेकेंडरी एज्युकेशनएचएससी विज्ञान कक्षा १२

Is it possible to store copper sulphate in an iron vessel for a long time? Given: EXCu2+|Cu0 = 0.34 V and EXFe2+|Fe0 = −0.44 V - Chemistry

Advertisements
Advertisements

प्रश्न

Is it possible to store copper sulphate in an iron vessel for a long time?

Given: \[\ce{E^0_{{Cu^{2+}|{Cu}}}}\] = 0.34 V and \[\ce{E^0_{{Fe^{2+}|{Fe}}}}\] = −0.44 V

टिप्पणी लिखिए
Advertisements

उत्तर

\[\ce{(E^0_{ox})_{{{Fe|{Fe^{2+}}}}}}\]= −0.44 V and \[\ce{(E^0_{red})_{{{Cu^{2+}|{Cu}}}}}\] = 0.34 V

These +ve emf values show that iron will oxidise and copper will get reduced i.e., the vessel will dissolve. Hence it is not possible to store copper sulphate in an iron vessel.

shaalaa.com
  क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
अध्याय 9: Electro Chemistry - Evaluation [पृष्ठ ६६]

APPEARS IN

सामाचीर कलवी Chemistry - Volume 1 and 2 [English] Class 12 TN Board
अध्याय 9 Electro Chemistry
Evaluation | Q 15. | पृष्ठ ६६

संबंधित प्रश्न

cell for the given redox reaction is 2.71 V
Mg(s) + Cu2+ (0.01 M) → Mg2+ (0.001 M) + Cu(s)

Calculate Ecell for the reaction. Write the direction of flow of current when an external opposite potential applied is
(i) less than 2.71 V and
(ii) greater than 2.71 V


What is the SI unit tor electrochemical equivalent?


In the electrochemical cell: Zn|ZnSO4 (0.01 M)||CuSO4 (1.0 M)|Cu, the emf of this Daniel cell is E1. When the concentration of ZnSO4 is changed to 1.0 M and that CuSO4 changed to 0.01 M, the emf changes to E2. From the above, which one is the relationship between E1 and E2?


A gas X at 1 atm is bubbled through a solution containing a mixture of 1 MY and 1 MZ at 25°C. If the reduction potential of Z > Y > X, then ______.


Why is anode in galvanic cell considered to be negative and cathode positive electrode?


`E_(cell)^Θ` for some half cell reactions are given below. On the basis of these mark the correct answer.

(a) \[\ce{H^{+} (aq) + e^{-} -> 1/2 H_2 (g); E^Θ_{cell} = 0.00V}\]

(b) \[\ce{2H2O (1) -> O2 (g) + 4H^{+} (aq) + 4e^{-}; E^Θ_{cell} = 1.23V}\]

(c) \[\ce{2SO^{2-}_{4} (aq) -> S2O^{2-}_{8} (aq) + 2e^{-}; E^Θ_{cell} = 1.96V}\]

(i) In dilute sulphuric acid solution, hydrogen will be reduced at cathode.

(ii) In concentrated sulphuric acid solution, water will be oxidised at anode.

(iii) In dilute sulphuric acid solution, water will be oxidised at anode.

(iv) In dilute sulphuric acid solution, \[\ce{SO4^{2-}}\] ion will be oxidised to tetrathionate ion at anode.


How will the pH of brine (aq. \[\ce{NaCl}\] solution) be affected when it is electrolysed?


Consider a cell given below:
\[\ce{Cu | Cu^{2+} || Cl^{-} | Cl_{2},Pt}\]
Write the reactions that occur at anode and cathode


On which electrode the oxidation reaction takes place?


Explain the types of electrochemical cells.


Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×