हिंदी

Consider the change in the oxidation state of Bromine corresponding to different emf values as shown in the expression below: BrO-_4 ->[1.82 V] BrO-_3 ->[1.5 V] HBrO ->[1.595 V] Br2 ->[1.0652 V] Br-

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प्रश्न

Consider the change in the oxidation state of Bromine corresponding to different emf values as shown in the expression below:

\[\ce{BrO^-_4 ->[1.82 V] BrO^-_3 ->[1.5 V] HBrO ->[1.595 V] Br2 ->[1.0652 V] Br^-}\]

Then the species undergoing disproportionation is:

विकल्प

  • Br2

  • \[\ce{BrO^-_4}\]

  • \[\ce{BrO^-_3}\]

  • HBrO

MCQ
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उत्तर

HBrO

Explanation:

(Ecell)A = – 1.82 + 1.5 = – 0.32 V

(Ecell)B = – 1.5 + 1.595 = + 0.095 V

(Ecell)C = 1.595 + 1.0652 = – 0.529 V

∴ The species undergoing disproportionation is HBrO.

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अध्याय 9: Electro Chemistry - Evaluation [पृष्ठ ६५]

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सामाचीर कलवी Chemistry - Volume 1 and 2 [English] Class 12 TN Board
अध्याय 9 Electro Chemistry
Evaluation | Q 21. | पृष्ठ ६५
नूतन Chemistry [English] Class 12 ISC
अध्याय 2 Electrochemistry
OBJECTIVE (MULTIPLE CHOICE) TYPE QUESTIONS | Q 71. | पृष्ठ २०१

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