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प्रश्न
In Young's double-slit experiment, the two slits are separated by a distance of 1.5 mm, and the screen is placed 1 m away from the plane of the slits. A beam of light consisting of two wavelengths of 650 nm and 520 nm is used to obtain interference fringes.
Find the distance of the third bright fringe for λ = 520 nm on the screen from the central maximum.
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उत्तर
Third bright fringe for λ1 = 520 nm is given by
`"x"_3 = (3lamda"D")/"d" = (3 xx 520 xx 10^-9 xx 1)/(1.5 xx 10^-3) = 1.04 xx 10^-3"m"`
= 1.04 mm.
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संबंधित प्रश्न
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REASON (R): Fringe width is proportional to (d/D).
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