हिंदी

In a Typical Nuclear Reaction, E.G. _1^2h+ 2 1 H → 3 2 H E + N + 3.27 Mev , Although Number of Nucleons is Conserved, Yet Energy is Released. How? Explain.

Advertisements
Advertisements

प्रश्न

 In a typical nuclear reaction, e.g.

`"_1^2H+"_1^2H ->"_2^3He + n + 3.27 \text { MeV },`

although number of nucleons is conserved, yet energy is released. How? Explain.

Advertisements

उत्तर

In a nuclear reaction, the sum of the masses of the target nucleus `("_1^2H)`and the bombarding particle `("_1^2H)`  may be greater or less than the sum of the masses of the product nucleus `("_1^3He)` and the outgoing particle `("_0^1n).`  So from the law of conservation of mass-energy some energy (3.27 MeV) is evolved or involved in a nuclear reaction. This energy is called Q-value of the nuclear reaction.

shaalaa.com
  क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
2012-2013 (March) Delhi Set 2
Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×