हिंदी

In the nuclear reaction, \\ce{^235_92U + ^1_0n -> X + ^90_37Pb + 2^1_0n}\, the element X is:

Advertisements
Advertisements

प्रश्न

In the nuclear reaction, \[\ce{^235_92U + ^1_0n -> X + ^90_37Pb + 2^1_0n}\], the element X is:

विकल्प

  • \[\ce{^144_55Cs}\]

  • \[\ce{^144_54Ba}\]

  • \[\ce{^142_55La}\]

  • \[\ce{^145_55Xe}\]

MCQ
Advertisements

उत्तर

\[\ce{^144_55Cs}\]

Explanation:

Mass number:

235 + 1 = AX ​+ 90 + 2

AX ​= 144

Atomic number:

92 = ZX ​+ 37

ZX ​= 55

Atomic number 55 = Caesium (Cs).

Therefore, X = \[\ce{^144_55Cs}\]

shaalaa.com

Notes

There is a printing error in the options. The correct answer is \[\ce{^144_55Cs}\]​ (Cesium-144). If Option 1 is intended to represent this, the element symbol should be Cs instead of Ba.

  क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
अध्याय 12: Modern Physics - Intex Question [पृष्ठ २९७]

APPEARS IN

लखमीर सिंग Physics [English] Class 10 ICSE
अध्याय 12 Modern Physics
Intex Question | Q 7. (i) | पृष्ठ २९७
Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×