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प्रश्न
In the nuclear reaction, \[\ce{^235_92U + ^1_0n -> X + ^90_37Pb + 2^1_0n}\], the element X is:
पर्याय
\[\ce{^144_55Cs}\]
\[\ce{^144_54Ba}\]
\[\ce{^142_55La}\]
\[\ce{^145_55Xe}\]
MCQ
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उत्तर
\[\ce{^144_55Cs}\]
Explanation:
Mass number:
235 + 1 = AX + 90 + 2
AX = 144
Atomic number:
92 = ZX + 37
ZX = 55
Atomic number 55 = Caesium (Cs).
Therefore, X = \[\ce{^144_55Cs}\]
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Notes
There is a printing error in the options. The correct answer is \[\ce{^144_55Cs}\] (Cesium-144). If Option 1 is intended to represent this, the element symbol should be Cs instead of Ba.
या प्रश्नात किंवा उत्तरात काही त्रुटी आहे का?
पाठ 12: Modern Physics - Intex Question [पृष्ठ २९७]
