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In the given figure ray AZ bisects ∠ BAD and ∠ DCB, prove that AB = AD - Mathematics

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प्रश्न

In the given figure ray AZ bisects ∠BAD and ∠DCB, prove that AB = AD

योग
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उत्तर

In ∆BAC and ∆DAC

∠BAC = ∠DAC ...[Given `bar("AZ")` bisects ∠BAD]

∠BCA = ∠DCA  ...[`bar("AZ")` bisects ∠DCB]

AC = AC  ...[∵ common side]

∴ Here AC is the included side of the angles

By ASA criterior, ∆BAC ≅ ∆DAC .......(i)

From (i) ∆BAC ≅ ∆DAC

BA = DA  ...[By CPCTC]

i.e., AB = AD

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अध्याय 4: Geometry - Exercise 4.3 [पृष्ठ ८६]

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सामाचीर कलवी Mathematics - Term 2 [English] Class 7 TN Board
अध्याय 4 Geometry
Exercise 4.3 | Q 8. (ii) | पृष्ठ ८६

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