Question

In the given figure, PQR is a tangent to the circle at Q, whose centre is O and AB is a chord parallel to PR such that ∠BQR = 70°. Then, AQB = ?

विकल्प

• 20°

• 35°

• 40°

• 45°

Answer 1

40°

Explanation:

∠QAB = ∠BQR = 70°   ...[Angles in alternate segments]

∠ABQ = ∠BQR = 70°   ...[Alternate int. angles]

In ΔAQB, we have

∠AQB = 180° – (∠QAB + ∠ABQ)

= 180° – (70° + 70°) 

= 40°