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प्रश्न
In the given figure, O is the centre of the circle and TP is the tangent to the circle from an external point T. If ∠PBT = 30°, prove that BA:AT = 2:1.

योग
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उत्तर
x + x = 60 = 180°
2x + 120°
x = 60°
y + 60 = 180°
y = 120°
∠TPA = 90° - 60 = 30°
30 + y + ∠T = 180°
30 + 120 + ∠T = 180°
150° + ∠T = 180°
∠T = 30°
`(BA)/(AT) = (2r)/r = 2/1`
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