Advertisements
Advertisements
प्रश्न
In the following problems use the factor theorem to find if g(x) is a factor of p(x):
p(x) = x3 - 3x2 + 4x - 4 and g(x) = x - 2
Advertisements
उत्तर
p(x) = x3 - 3x2 + 4x - 4 and g(x) = x - 2
To check whether x - 2 is a factor of p(x) now put x = 2 in equation (i), we get
p(2) = (2)3 - 3(2)2 + 4(2) -4
= 8 - 3 x 4 + 8 - 4
= 8 - 12 + 8 - 4
= 16 - 16 = 0
Since, p(2) = 0, so by factor theorem (x - 2) is a factor of p(x).
संबंधित प्रश्न
Show that 3x + 2 is a factor of 3x2 – x – 2.
If x – 2 is a factor of x2 + ax + b and a + b = 1, find the values of a and b.
Prove by factor theorem that
(3x-2) is a factor of 18x3 - 3x2 + 6x -12
Find the value of m ·when x3 + 3x2 -m x +4 is exactly divisible by (x-2)
Prove that ( p-q) is a factor of (q - r)3 + (r - p) 3
Prove that (x-3) is a factor of x3 - x2 - 9x +9 and hence factorize it completely.
Find the value of a , if (x - a) is a factor of x3 - a2x + x + 2.
Given that x + 2 and x + 3 are factors of 2x3 + ax2 + 7x - b. Determine the values of a and b.
Using factor theorem, show that (x - 3) is a factor of x3 - 7x2 + 15x - 9, Hence, factorise the given expression completely.
Show that (x – 3) is a factor of x3 – 7x2 + 15x – 9. Hence factorise x3 – 7x2 + 15 x – 9
