Advertisements
Advertisements
प्रश्न
In the following, find the marked unknown angle:

Advertisements
उत्तर
Since, sum of all angles of triangle = 180°
1st Triangle 50° + 80° + b = 180°
⇒ 130°+ &= 180°
⇒ b = 180° – 130°
b = 50°
II nd Triangle 40° + 45° + a = 180°
⇒ 85° + a = 180°
⇒ a = 180° - 85
a = 95°
APPEARS IN
संबंधित प्रश्न
If the angles of a triangle are in the ratio 1: 2 : 3, determine three angles.
In a ΔABC, ∠ABC = ∠ACB and the bisectors of ∠ABC and ∠ACB intersect at O such that ∠BOC = 120°. Show that ∠A = ∠B = ∠C = 60°.
Can a triangle have All angles equal to 60°? Justify your answer in case.
Is the following statement true and false :
All the angles of a triangle can be equal to 60°.
In a Δ ABC, the internal bisectors of ∠B and ∠C meet at P and the external bisectors of ∠B and ∠C meet at Q, Prove that ∠BPC + ∠BQC = 180°.
In the given figure, side BC of ΔABC is produced to point D such that bisectors of ∠ABC and ∠ACD meet at a point E. If ∠BAC = 68°, find ∠BEC.

One angle of a triangle is 61° and the other two angles are in the ratio `1 1/2: 1 1/3`. Find these angles.
One of the base angles of an isosceles triangle is 52°. Find its angle of the vertex.
The length of the sides of the triangle is given. Say what types of triangles they are 4.3 cm, 4.3 cm, 4.3 cm.
In the given figure, AB is parallel to CD. Then the value of b is
