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प्रश्न
In the following figure is a sector of circle of radius 10.5 cm. Find the perimeter of the sector. `("Take" π = 22/7)`
योग
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उत्तर
Perimeter of the sector
= `2r + (2πrθ)/(360^circ)`
= `2 xx 10.5 + (2 xx 22 xx 10.5 xx 60^circ)/(7 xx 360^circ)`
= 21 + 11
= 32 cm
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