Advertisements
Advertisements
प्रश्न
In the following figure, if ∠OAB = 40º, then ∠ACB is equal to ______.
विकल्प
50º
40º
60º
70°
Advertisements
उत्तर
In the following figure, if ∠OAB = 40º, then ∠ACB is equal to 50º.
Explanation:
Given: ∠OAB = 40º
Now, in triangle OAB,
OA = OB ...[Radii of circle]
So, ∠OAB = ∠OBA = 40º ...[Angle opposite to equal sides are equal]
So, ∠AOB = 180º – (40º + 40º) = 100º
As we know that angle subtended by an arc of a circle at the center is double the angle subtended by it at any point on the remaining part of the circle.
So, ∠ACB = `1/2` ∠AOB = `1/2 xx 100^circ` = 50º
APPEARS IN
संबंधित प्रश्न
In Fig. 8, O is the centre of a circle of radius 5 cm. T is a point such that OT = 13 cm and OT intersects circle at E. If AB is a tangent to the circle at E, find the length of AB, where TP and TQ are two tangents to the circle.
Write True or False. Give reason for your answer.
A circle has only finite number of equal chords.
If PT is a tangent at T to a circle whose center is O and OP = 17 cm, OT = 8 cm. Find the length of tangent segment PT.
In Fig. 4, an isosceles triangle ABC, with AB = AC, circumscribes a circle. Prove that the point of contact P bisects the base BC.
The circumference of a circle is 22 cm. The area of its quadrant (in cm2) is
In the given figure, if chords AB and CD of the circle intersect each other at right angles, then x + y =
Use the figure given below to fill in the blank:
R is the _______ of the circle.
In the figure, segment PQ is the diameter of the circle with center O. The tangent to the tangent circle drawn from point C on it, intersects the tangents drawn from points P and Q at points A and B respectively, prove that ∠AOB = 90°
In the figure, a circle with center P touches the semicircle at points Q and C having center O. If diameter AB = 10, AC = 6, then find the radius x of the smaller circle.
In the following figure, O is the centre of the circle, ∠BCO = 30°. Find x and y.
