Advertisements
Advertisements
प्रश्न
In the following figure, if ∠OAB = 40º, then ∠ACB is equal to ______.
विकल्प
50º
40º
60º
70°
Advertisements
उत्तर
In the following figure, if ∠OAB = 40º, then ∠ACB is equal to 50º.
Explanation:
Given: ∠OAB = 40º
Now, in triangle OAB,
OA = OB ...[Radii of circle]
So, ∠OAB = ∠OBA = 40º ...[Angle opposite to equal sides are equal]
So, ∠AOB = 180º – (40º + 40º) = 100º
As we know that angle subtended by an arc of a circle at the center is double the angle subtended by it at any point on the remaining part of the circle.
So, ∠ACB = `1/2` ∠AOB = `1/2 xx 100^circ` = 50º
APPEARS IN
संबंधित प्रश्न
Two circles touch each other externally at P. AB is a common tangent to the circles touching them at A and B. The value of ∠ L APB is
(A) 30°
(B) 45°
(C) 60°
(D) 90°
In fig. XP and XQ are tangents from X to the circle with centre O. R is a point on the circle. Prove that, XA + AR = XB + BR.
Write True or False. Give reason for your answer.
Sector is the region between the chord and its corresponding arc.
In the given figure, chords AD and BC intersect each other at right angles at a point P. If ∠DAB = 35°, then
If all the sides of a parallelogram touch a circle, show that the parallelogram is a rhombus.
Draw circle with diameter: 6 cm
In above case, measure the length of the radius of the circle drawn.
Draw circle with the radii given below.
3 cm
A line segment with its end points on the circle is called a ______________
If A, B, C, D are four points such that ∠BAC = 30° and ∠BDC = 60°, then D is the centre of the circle through A, B and C.
From the figure, identify two points in the interior.
