Question

In the circuit shown below:  

 

The potential difference across the 3 Ω resistor is:

विकल्प

• `1/9`V

• `1/2` V

• 1 V

• 2 V

Answer 1

1V
The resistors of 1 Ω, 2 Ω and 3 Ω  are connected in series. Therefore, the net resistance,
R = R₁ +R₂ +R₃
R = 1 Ω + 2 Ω + 3 Ω = 6 Ω
Current in the circuit will be,
I = V/R
or I = 2/6 = 1/3 A
Current = `1/3`A
Therefore, the voltage across the 3 Ώ resistor,
V = IR
or V= `1/3xx3` = 1 V