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प्रश्न
In the adjoining figure, ABCD is a rectangle in which AB = 10 cm, AD = 6 cm. If AP || BQ, find :
- ar (|| gm ABQP)
- ar (ΔАВР)

योग
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उत्तर
Given: ABCD is a rectangle with AB = 10 cm, AD = 6 cm. AP || BQ.
Step-wise calculation:
1. Parallelogram ABQP:
Base = AB = 10 cm.
The distance (height) between AB and PQ equals AD = 6 cm.
P and Q lie on the line through DC, parallel to AB.
Area (parallelogram) = Base × Height
= 10 × 6
= 60 cm2
2. Triangle ABP:
Base = AB = 10 cm
Height = AD = 6 cm
Area (triangle) = `1/2` × Base × Height
= `1/2 xx 10 xx 6`
= 30 cm2
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