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In a Radioactive Decay, Neither the Atomic Number Nor the Mass Number Changes. Which of the Following Particles is Emitted in the Decay? - Physics

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प्रश्न

In a radioactive decay, neither the atomic number nor the mass number changes. Which of the following particles is emitted in the decay?

विकल्प

  • Proton

  • Neutron

  • Electron

  • Photon

MCQ
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उत्तर

Photon 

The atomic number and mass number of a nucleus is defined as the number of protons and the sum of the number of protons and neutrons present in the nucleus, respectively. Since in the decay, neither the atomic number nor the mass number change, it cannot be a beta-decay (release of electron, proton or neutron). Hence, the particle emitted can only be a photon.

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अध्याय 24: The Nucleus - MCQ [पृष्ठ ४४१]

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एचसी वर्मा Concepts of Physics Vol. 2 [English] Class 11 and 12
अध्याय 24 The Nucleus
MCQ | Q 12 | पृष्ठ ४४१

संबंधित प्रश्न

 

(a) Write the basic nuclear process involved in the emission of β+ in a symbolic form, by a radioactive nucleus.

(b) In the reactions given below:

(i)`""_16^11C->_y^zB+x+v`

(ii)`""_6^12C+_6^12C->_a^20 Ne + _b^c He`

Find the values of x, y, and z and a, b and c.

 

State the law of radioactive decay.


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The radionuclide 11C decays according to 

\[\ce{^11_6C -> ^11_5B + e+ + \text{v}}\] : T1/2 = 20.3 min

The maximum energy of the emitted positron is 0.960 MeV.

Given the mass values: `"m"(""_6^11"C") = 11.011434 u and "m"(""_6^11"B") = 11.009305 "u"`

Calculate Q and compare it with the maximum energy of the positron emitted.


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`""^228"Th" → ""^224"Ra"^(∗) + alpha`

`""^224"Ra"^(∗) → ""^224"Ra" + γ (217 "keV")`.

Atomic mass of 228Th is 228.028726 u, that of 224Ra is 224.020196 u and that of  `""_2^4H` is 4.00260 u.

(Use Mass of proton mp = 1.007276 u, Mass of `""_1^1"H"` atom = 1.007825 u, Mass of neutron mn = 1.008665 u, Mass of electron = 0.0005486 u ≈ 511 keV/c2,1 u = 931 MeV/c2.)


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(a) What fraction of carbon atoms were 14C?
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