Advertisements
Advertisements
प्रश्न
In the given figure, if CP || DQ, then the measure of x is
विकल्प
130°
105°
175°
125°
Advertisements
उत्तर
Let us extend PC to meet AB at point O.
It is given that BQ || PO.
Thus,∠QBOand ∠AOP are corresponding angles. Therefore,
∠AOP = ∠QBO
Given that ∠QBO = 150°, then we have:
∠AOP = 105V
Or,
∠AOC =105°
Also, in ΔAOC, exterior angle is equal to the sum of the interior opposite angles, therefore,
x = ∠AOC + ∠COA
x = 105° + 25°
x = 130°
APPEARS IN
संबंधित प्रश्न
In the given below fig, rays OA, OB, OC, OP and 0E have the common end point O. Show
that ∠AOB + ∠BOC + ∠COD + ∠DOE + ∠EOA = 360°.
Fill in the blank so as to make the following statement true:
If the sum of two adjacent angles is 180°, then the ______ arms of the two angles are
opposite rays
If two straight lines intersect each other, prove that the ray opposite to the bisector of one of the angles thus formed bisects the vertically opposite angle.
The complement of an acute angle is ..............
An angle is equal to its supplement. Determine its measure.
One angle is equal to three times its supplement. The measure of the angle is
Two straight lines AB and CD cut each other at O. If ∠BOD = 63°, then ∠BOC =
In the given figure, AB || CD || EF and GH || KL. The measure of ∠HKL is
In the adjoining figure, if b° = a° + c°, find b.
Write the complement of `1/3` of 180°
