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प्रश्न
In the given figure, if CP || DQ, then the measure of x is
पर्याय
130°
105°
175°
125°
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उत्तर
Let us extend PC to meet AB at point O.
It is given that BQ || PO.
Thus,∠QBOand ∠AOP are corresponding angles. Therefore,
∠AOP = ∠QBO
Given that ∠QBO = 150°, then we have:
∠AOP = 105V
Or,
∠AOC =105°
Also, in ΔAOC, exterior angle is equal to the sum of the interior opposite angles, therefore,
x = ∠AOC + ∠COA
x = 105° + 25°
x = 130°
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संबंधित प्रश्न
In the given below fig, rays OA, OB, OC, OP and 0E have the common end point O. Show
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