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In the Given Cases, Find the Distance of Each of the Given Points from the Corresponding Given Plane. 2x – 3y + 6z – 2 = 0 - Mathematics

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प्रश्न

In the given cases, find the distance of each of the given points from the corresponding given plane.

Point              Plane

(– 6, 0, 0)        2x – 3y + 6z – 2 = 0

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उत्तर

It is known that the distance between a point, p(x1y1z1), and a plane, Ax + By + Cz = D, is given by,

The given point is (−6, 0, 0) and the plane is 2x – 3y + 6z – 2 = 0

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  क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
अध्याय 11: Three Dimensional Geometry - Exercise 11.3 [पृष्ठ ४९४]

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एनसीईआरटी Mathematics Part 1 and 2 [English] Class 12
अध्याय 11 Three Dimensional Geometry
Exercise 11.3 | Q 14.4 | पृष्ठ ४९४

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संबंधित प्रश्न

In the given cases, find the distance of each of the given points from the corresponding given plane.

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