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In a Gamma Decay Process, the Internal Energy of a Nucleus of Mass M Decreases, a Gamma Photon of Energy E and Linear

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प्रश्न

In a gamma decay process, the internal energy of a nucleus of mass M decreases, a gamma photon of energy E and linear momentum E/c is emitted and the nucleus recoils. Find the decrease in internal energy. 

योग
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उत्तर

Let the nucleus recoils with a velocity v.

Applying  the law of conservation of linear momentum, we get: 
Linear momentum of recoiled nucleus  =  Linear momentum of gamma photon
⇒ mv = \[\frac{E}{c}\]
∴ \[v = \frac{E}{mc}\]
Kinetic energy of the recoiled nucleus = \[\frac{1}{2}M v^2\]
\[\Rightarrow K . E . = \frac{1}{2}m \left( \frac{E}{mc} \right)^2 = \frac{1}{2}\frac{E^2}{m c^2}\]
Decrease in the internal energy = photon energy + the kinetic energy of the recoiled nucleus
⇒ Decrease in the internal energy = \[E + \frac{E^2}{2m c^2}\]

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Momentum Conservation and Centre of Mass Motion
  क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
अध्याय 9: Centre of Mass, Linear Momentum, Collision - Exercise [पृष्ठ १६२]

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एचसी वर्मा Concepts of Physics Volume 1 and 2 [English]
अध्याय 9 Centre of Mass, Linear Momentum, Collision
Exercise | Q 40 | पृष्ठ १६२

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