Advertisements
Advertisements
प्रश्न
In each of the following determine whether the given values are solutions of the equation or not.
3x2 - 2x - 1 = 0; x = 1
Advertisements
उत्तर
Given equation is
3x2 - 2x - 1 = 0; x = 1
Put x = 1 in the L.H.S.
L.H.S. = 3(1)2 - 2 x 1 - 1
= 3 - 3
= 0
= R.H.S.
Hence, x = 1 is a solution of the given equation.
संबंधित प्रश्न
Solve the following quadratic equations by factorization:
`(x-a)/(x-b)+(x-b)/(x-a)=a/b+b/a`
Solve:
(a + b)2x2 – (a + b)x – 6 = 0; a + b ≠ 0
If sin α and cos α are the roots of the equations ax2 + bx + c = 0, then b2 =
If an integer is added to its square the sum is 90. Find the integer with the help of a quadratic equation.
Find two consecutive positive even integers whose squares have the sum 340.
Solve the following quadratic equation by factorisation:
(2x + 3) (3x - 7) = 0
Solve the following equation by factorization
3x2= x + 4
Solve the following equation by factorization
`(1)/(7)(3x – 5)^2`= 28
The age of a man is twice the square of the age of his son. Eight years hence, the age of the man will be 4 years more than three times the age of his son. Find the present age.
Solve the following equation by factorisation :
x(x + 1) + (x + 2)(x + 3) = 42
