हिंदी

In ΔABC, it is given that AB = 9 cm, BC = 6 cm and CA = 7.5 cm. Also, ΔDEF is given such that EF = 8 cm and ΔDEF ~ ΔABC. Then, perimeter of ΔDEF is ______.

Advertisements
Advertisements

प्रश्न

In ΔABC, it is given that AB = 9 cm, BC = 6 cm and CA = 7.5 cm. Also, ΔDEF is given such that EF = 8 cm and ΔDEF ~ ΔABC. Then, perimeter of ΔDEF is ______.

विकल्प

  • 22.5 cm

  • 25 cm

  • 27 cm

  • 30 cm

MCQ
रिक्त स्थान भरें
Advertisements

उत्तर

In ΔABC, it is given that AB = 9 cm, BC = 6 cm and CA = 7.5 cm. Also, ΔDEF is given such that EF = 8 cm and ΔDEF ~ ΔABC. Then, perimeter of ΔDEF is 30 cm.

Explanation:

Because ΔDEF ~ ΔABC the vertex order gives D ↔ A, E ↔ B, F ↔ C, so EF corresponds to BC and corresponding sides are in the same ratio.

Thus, scale factor `k = (EF)/(BC)`

= `8/6`

= `4/3` 

Perimeter of ABC = 9 + 6 + 7.5

= 22.5 cm 

Perimeter of DEF = k × 22.5

= `4/3 xx 22.5`

= 30 cm

shaalaa.com
  क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
अध्याय 7: Triangles - MULTIPLE-CHOICE QUESTIONS (MCQ) [पृष्ठ ४५४]

APPEARS IN

आर.एस. अग्रवाल Mathematics [English] Class 10
अध्याय 7 Triangles
MULTIPLE-CHOICE QUESTIONS (MCQ) | Q 29. | पृष्ठ ४५४
Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×