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प्रश्न
In a single slit diffraction experiment, the width of the slit is made double the original width. How does this affect the size and intensity of the central diffraction band?
In a single slit diffraction experiment, the width of the slit is made double the original width. How does this affect the size and intensity of the central diffraction band? Explain
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उत्तर १
In a single slit diffraction experiment, if the width of the slit is made double the original width, then the size of the central diffraction band reduces to half and the intensity of the central diffraction band increases up to four times.
उत्तर २
Size of central diffraction pattern = `(2"D"lambda)/"a"`
where a is the width of the slit. Thus, if the width of the single slit is doubled than the original width, then the size of the central diffraction pattern halves.
Now, as the size of the central diffraction pattern becomes half, the area of central diffraction pattern will become one-fourth. Thus, the intensity of central diffraction pattern will become four times.
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संबंधित प्रश्न
In what way is diffraction from each slit related to the interference pattern in a double-slit experiment?
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How does the intensity of secondary maxima change as you move away from the centre?
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Which equation equates the top-to-middle path difference to the value required for destructive interference?
Into how many equal parts can the slit be divided to generalise the condition for minima?
Why are secondary maxima much weaker than the central maximum?
How does the intensity change on both sides of \[\theta=0\]?
What happens to the intensity of the secondary maxima as \[n\] increases?
