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In a Rectangle Abcd, Prove That: Ac2 + Bd2 = Ab2 + Bc2 + Cd2 + Da2. - Mathematics

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प्रश्न

In a rectangle ABCD,
prove that: AC2 + BD2 = AB2 + BC2 + CD2 + DA2.

योग
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उत्तर


Pythagoras theorem states that in a right-angled triangle, the square on the hypotenuse is equal to the sum of the squares on the remaining two sides.
Since, ABCD is a rectangle angles A, B, C and D are rt. angles.

First, we consider the ΔACD, and applying Pythagoras theorem we get,
AC2 = DA2 + CD                 ....(i)

Similarly, we get from rt. angle triangle BDC we get,
BD2 = BC2 + CD2
= BC2 + AB2          ....[ In a rectangle, opposite sides are equal, ∴ CD = AB ] ...(ii)

Adding (i) and (ii)
AC2 + BD2 = AB2 + BC2 + CD2 + DA2
Hence proved.

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  क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
अध्याय 13: Pythagoras Theorem [Proof and Simple Applications with Converse] - Exercise 13 (B) [पृष्ठ १६४]

APPEARS IN

सेलिना Concise Mathematics [English] Class 9 ICSE
अध्याय 13 Pythagoras Theorem [Proof and Simple Applications with Converse]
Exercise 13 (B) | Q 6 | पृष्ठ १६४

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