हिंदी

In a park of dimensions 20 m × 15 m, there is a L shaped 1 m wide flower bed as shown in the following figure. Find the total cost of manuring for the flower bed at the rate of Rs 45 per m2.

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प्रश्न

In a park of dimensions 20 m × 15 m, there is a L shaped 1 m wide flower bed as shown in the following figure. Find the total cost of manuring for the flower bed at the rate of Rs 45 per m2.

आकृति
योग
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उत्तर


Given, dimensions of a park = 20 m × 15 m and with of a flower bed = 1 m

From the figure,

FG = BC – 1 m = (15 – 1) = 14 m

EF = DC – 1 m = (20 – 1) = 19 m

∴ Area of flower bed = Area of ABCD – Area of EFGD

= 20 × 15 – 19 × 14  ...[∵ Area of rectangle = Length × Breadth]

= 300 – 266

= 34 m2

∵ Cost of manuring 1 m2 of flower bed = ₹ 45

∴ Cost of manuring 34 m2 the flower bed of = ₹ 34 × 45 = ₹ 1530

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अध्याय 9: Perimeter and Area - Exercise [पृष्ठ २९३]

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एनसीईआरटी एक्झांप्लर Mathematics [English] Class 7
अध्याय 9 Perimeter and Area
Exercise | Q 116. | पृष्ठ २९३

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