Advertisements
Advertisements
प्रश्न
If `1/12` , x and `1/75` are in continued proportion , find x.
Advertisements
उत्तर
Since `1/12` , x and `1/75` are in continued proportion.
`=> 1/12 : "x" : : "x" : 1/75`
`=> "x"^2 = 1/12 xx 1/75`
`=> x = sqrt (1/900)`
`=> "x"=1/30``1/30`
APPEARS IN
संबंधित प्रश्न
If `a/b = c/d` prove that each of the given ratios is equal to
`(5a + 4c)/(5b + 4d)`
Find two numbers whose mean proportional is 18 and the third proportional is 486.
If p, q and r in continued proportion, then prove the following:
(p2 - q2)(q2 + r2) = (q2 - r2)(p2 + q2)
If a, b, c and dare in continued proportion, then prove that
ad (c2 + d2) = c3 (b + d)
If a, b, c, d are in continued proportion, prove that:
`sqrt(ab) - sqrt(bc) + sqrt(cd) = sqrt((a - b + c) (b - c + d)`
Find the third proportional to 5, 10
If a, b, c, d are in proportion, then
If `x/a = y/b = z/c`, prove that `[(a^2x^2 + b^2y^2 + c^2z^2)/(a^2x + b^3y +c^3z)]^3 = "xyz"/"abc"`
If a, b, c and d are in proportion, prove that: `(a^2 + b^2)/(c^2 + d^2) = "ab + ad - bc"/"bc + cd - ad"`
12 : `square` = `square` : 4 = 8 : 16
