Question

If y = Ae^5x + Be^–5x, then `(d^2y)/(dx^2)` is equal to ______.

विकल्प

• 25y

• 5y

• –25y

• 15y

Answer 1

If y = Ae^5x + Be^–5x, then `(d^2y)/(dx^2)` is equal to 25y.

Explanation:

y = Ae^5x + Be^–5x

⇒ `dy/dx = 5Ae^(5x) - 5Be^(-5x)`

⇒ `(d^2y)/(d^2x) = 25Ae^(5x) + 25Be^(-5x)`

= 25y