Advertisements
Advertisements
प्रश्न
`int x^2 e^(x^3) dx` equals
विकल्प
`1/3 e^(x^3) + C`
`1/3 e^(x^4) + C`
`1/2 e^(x^3) + C`
`1/2 e^(x^2) + C`
Advertisements
उत्तर १
`bb(1/3 e^(x^3) + C)`
Explanation:
`int x^2 e^(x^3) dx` put x3 = t
∴ 3x2 dx = dt
= `1/3 int (3x^2) e^(x^3) dx`
= `1/3 int e^t dt`
= `1/3 e^t + C`
= `1/3 e^(x^3) + C`
उत्तर २
`bb(1/3 e^(x^3) + C)`
Explanation:
Given `int x^2 e^(x^3) dx`
Put x3 = y
⇒ 3x2dx = dy
Then `int x^2 e^(x^3) dx = 1/3 int e^y dy`
= `1/3 e^y + C`
= `1/3 e^(x^3) + C`
APPEARS IN
संबंधित प्रश्न
Write the antiderivative of `(3sqrtx+1/sqrtx).`
Evaluate : `∫(sin^6x+cos^6x)/(sin^2x.cos^2x)dx`
Find an anti derivative (or integral) of the following function by the method of inspection.
sin 2x
Find the following integrals:
`int (4e^(3x) + 1)`
Find the following integrals:
`int (ax^2 + bx + c) dx`
Find the following integrals:
`int(2x^2 + e^x)dx`
Find the following integrals:
`int(sqrtx - 1/sqrtx)^2 dx`
Find the following integrals:
`int (x^3 + 5x^2 -4)/x^2 dx`
Find the following integrals:
`int (2 - 3 sinx)/(cos^2 x) dx.`
The anti derivative of `(sqrtx + 1/ sqrtx)` equals:
If `d/dx f(x) = 4x^3 - 3/x^4` such that f(2) = 0, then f(x) is ______.
Integrate the function:
`1/(x - x^3)`
Integrate the function:
`1/(sqrt(x+a) + sqrt(x+b))`
Integrate the function:
`x^3/(sqrt(1-x^8)`
Integrate the function:
`1/((x^2 + 1)(x^2 + 4))`
Integrate the function:
f' (ax + b) [f (ax + b)]n
Integrate the function:
`(x^2 + x + 1)/((x + 1)^2 (x + 2))`
Integrate the function:
`(sqrt(x^2 +1) [log(x^2 + 1) - 2log x])/x^4`
Evaluate `int tan^(-1) sqrtx dx`
Evaluate: `int (1 - cos x)/(cos x(1 + cos x)) dx`
If `d/(dx) f(x) = 4x^3 - 3/x^4`, such that `f(2) = 0`, then `f(x)` is
`int (dx)/(sin^2x cos^2x) dx` equals
`int (dx)/sqrt(9x - 4x^2)` equal
`int (xdx)/((x - 1)(x - 2))` equals
`int (dx)/(x(x^2 + 1))` equals
`int e^x sec x(1 + tanx) dx` equals
`int sqrt(1 + x^2) dx` is equal to
What is anti derivative of `e^(2x)`
