Advertisements
Advertisements
प्रश्न
If x + y + z = 6 and z is an odd digit, then the three-digit number xyz is ______.
विकल्प
an odd multiple of 3
odd multiple of 6
even multiple of 3
even multiple of 9
Advertisements
उत्तर
If x + y + z = 6 and z is an odd digit, then the three-digit number xyz is an odd multiple of 3.
Explanation:
We have, x + y + z = 6 and z is an odd digit.
Since, sum of the digits is divisible by 3, it will also be divisible by 2 and 3 but unit digit is odd, so it is divisible by 3 only.
Hence, the number is an odd multiple of 3.
APPEARS IN
संबंधित प्रश्न
If 24x is a multiple of 3, where x is a digit, what is the value of x?
(Since 24x is a multiple of 3, its sum of digits 6 + x is a multiple of 3; so 6 + x is one of these numbers: 0, 3, 6, 9, 12, 15, 18…. But since x is a digit, it can only be that 6 + x = 6 or 9 or 12 or 15. Therefore, x = 0 or 3 or 6 or 9. Thus, x can have any of four different values)
If 31z5 is a multiple of 3, where z is a digit, what might be the values of z?
Given that the number \[\overline{{35\alpha64}}\] is divisible by 3, where α is a digit, what are the possible values of α?
Given that the number \[\overline{{67y19}}\] is divisible by 9, where y is a digit, what are the possible values of y?
Find the remainder when 51439786 is divided by 3. Do this without performing actual division.
Check the divisibility of 2146587 by 3.
If a number is divisible by 6, then it must be divisible by 3
Let abc be a three digit number. Then abc + bca + cab is not divisible by ______.
Number of the form 3N + 2 will leave remainder 2 when divided by 3.
What is the rule to check if a number is divisible by 3?
