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प्रश्न
If `x = (sqrt(m + n) + sqrt(m - n))/(sqrt(m + n) - sqrt(m - n))`, express n in terms of x and m.
योग
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उत्तर
`x = (sqrt(m + n) + sqrt(m - n))/(sqrt(m + n) - sqrt(m - n)`
Applying componendo and dividendo,
`(x + 1)/(x - 1) = (sqrt(m + n) + sqrt(m - n) + sqrt(m + n) - sqrt(m - n))/(sqrt(m + n) + sqrt(m - n) - sqrt(m + n) + sqrt(m - n))`
`(x + 1)/(x - 1) = (2sqrt(m + n))/(2sqrt(m - n))`
Squaring both sides,
`(x^2 + 2x + 1)/(x^2 - 2x + 1) = (m + n)/(m - n)`
Applying componendo and dividendo,
`(x^2 + 2x + 1 + x^2 - 2x + 1 )/(x^2 + 2x + 1 - x^2 + 2x - 1) =
(m + n + m - n)/(m + n - m + n)`
`(2x^2 + 2)/(4x) = (2m)/(2n)`
`(x^2 + 1)/(2x) = m/n`
`(x^2 + 1)/(2mx) = 1/n`
`n = (2mx)/(x^2 + 1)`
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